How many 3 digit numbers are there such that at least one of its digit is 6?

How many 3 digit numbers are there such that at least one of its digit is 6?

If exactly one digit is a 6, there are 1⋅9⋅9+8⋅1⋅9+8⋅9⋅1=225 possibilities. If exactly two digits are a 6, there are 9+9+8=26 possibilities. If exactly three digits are 6, there is only one possibility. Thus there are 252 possibilities in total.

How many 3 digit multiples does 7 have?

Answer: 3 – digit multiples of 7, ie 128-3 digit numbers that are divisible by 7.

How many three-digit numbers contain the digit 3 at least once?

So there are 8 x 9 x 9 of these. That’s 648 altogether. So the number of 3-digit numbers with at least one three is 900 – 648 = 252.

How many 3 digit numbers are there in all answer?

900 three-digit numbers
Therefore there are 900 three-digit numbers in all.

How many 3 digit numbers have at least one of their digits as 5?

Total three digit numbers having one or more 5 are 72+72+81=225 numbers.

How many 3 digit permutations of the odd digits are there if no digit repeats?

I know the answer is 5⋅8⋅8=320.

What is the first 3 digit multiple of 7?

Multiples of 7 = 7, 14, 21, 28, 35, 42, 49, 56, 63, 70 ………….so on. The first 3 digit even multiple of 7 is 112.

What are the 3 digit numbers divisible by 7?

Hence, 994 is the largest 3 digit number which is divisible by 7. So, the numbers that are divisible by 7 are: 105, 112, 119, ….., 987, 994.

How many 3 digits numbers do not contain any of the digits 3 or 5?

The correct is 288. My idea is, first I get the total number of 3-digit integers that do not contain 5, then divide it by 2. And because it is a 3-digit integer, the hundreds digit can not be zero. So, I have (8*9*9)/2 = 324.

How many numbers are there in all having 1 digit?

Typically, there are ten digits in the decimal number system, starting from 0 and counting up to 9. In the decimal number system, the smallest one digit number is 1. 9 is the highest one digit number. Therefore to answer the question, how many one digit numbers are there, there are ten one digit numbers including 0.

How many 3 digit combinations are there?

There are, you see, 3 x 2 x 1 = 6 possible ways of arranging the three digits. Therefore in that set of 720 possibilities, each unique combination of three digits is represented 6 times. So we just divide by 6. 720 / 6 = 120.